How Calculate Cat's Jump?

Hello Physics Mavens,

Just watched one of my cats make two upward jumps; both with pinpoint accuracy.

(Cats are amazing creatures.)

One height was ~74cm above the floor; the other height ~81cm. He cleared both ledges by ~3cm and softly touched down on his paws at--what seems to be--near zero velocity.

In addition to being amazed by the accuracy of his internal computer...I wonder how one calculates the force he puts into each jump? Assuming there's a physics formula(s)--would you be so kind as to post an approach/solution?

CAT's weight: ~0.465kg
Height of First Ledge*: ~74cm
Height of Second Ledge*: ~81cm

*To clarify: He jumped from the floor to the first ledge...jumped back (down) to the floor...then jumped up to the second ledge--in this observation, he did not jump from the first ledge to the second.

If F = ma = gm; how much 'a' does he exert when leaving the ground such that his 'a' at (near) the desired height (+ ~3cm) approaches zero?

Also, is there a way to calculate the duration (time) of his jump?

Best regards,
Plane Wryter

You can use energy conservation to get the initial velocity he needs to attain to reach the heights required: $\frac{1}{2}mv^2=mgh$. With this velocity, you know the change in momentum $\Delta p = mv$, and therefore the total impulse $I=F_{tot}\Delta t=\Delta p$