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Just watched one of my cats make two upward jumps; both with pinpoint accuracy.

(Cats are amazing creatures.)

One height was ~74cm above the floor; the other height ~81cm. He cleared both ledges by ~3cm and softly touched down on his paws at--what seems to be--near zero velocity.

In addition to being amazed by the accuracy of his internal computer...I wonder how one calculates the force he puts into each jump? Assuming there's a physics formula(s)--would you be so kind as to post an approach/solution?

CAT's weight: ~0.465kg

Height of First Ledge*: ~74cm

Height of Second Ledge*: ~81cm

**To clarify: He jumped from the floor to the first ledge...jumped back (down) to the floor...then jumped up to the second ledge--in this observation, he did*

**not**jump from the first ledge to the second.If

**F = ma = gm**; how much '

*a*' does he exert when leaving the ground such that his '

*a*' at (near) the desired height (+ ~3cm) approaches zero?

Also, is there a way to calculate the duration (time) of his jump?

Many, many thanks in advance.

Best regards,

*Plane Wryter*