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How can a light bulb be made more efficient so that it emits more light in the visible spectrum?

  1. Oct 14, 2014 #1
    I just finished an experiment on blackbody radiation, and one of the post lab questions asked me on the possible ways in which a light bulb can be made more efficient such that the majority of the light it produces falls in the visible spectrum.

    After some quick research I think one of the ways is to replace the filament with a semiconductor material so that the lightbulb essentially becomes an LED, but I'm not sure if that fully answers the question. I appreciate any help!
     
  2. jcsd
  3. Oct 14, 2014 #2

    phinds

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    If you do that, what you have is just an LED bulb, which you can already buy, so that isn't a NEW way to do it but it certainly IS a way to do it.
     
  4. Oct 14, 2014 #3

    Doug Huffman

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    What does an Edison incandescent filament lightbulb emit other than visible light that might be converted to visible light?
     
  5. Oct 14, 2014 #4

    NTW

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    In an incandescent light bulb, there is a lot of energy emitted in infrared wavelengths. There is an easy way to increase the visible-light component, but at a cost...
     
  6. Oct 14, 2014 #5
    Is it to choose a filament whose metal has a very high melting point and/or simply make the lightbulb dimmer?
     
  7. Aug 13, 2015 #6
    Hi all,

    I'm joining this thread as I have a question related to the topic of IR/visible light radiation from light bulbs. I've built a multitouch display using infra-red light, and I found that the ambient light from my ceiling light bulb is interfering with my device. I was wondering if changing my light bulb (a halogen) to an LED energy saving light bulb would reduce the amount of IR emitted ?

    Thanks
     
  8. Aug 13, 2015 #7

    BvU

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    Better to post a new thread. ANd to do some googleing beforehand. Plenty of answers around ! e.g. here

    spectral_responses2.png
     
  9. Aug 13, 2015 #8
    Thank you. Apologies for messing up with the thread.
     
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