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gigi9
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Help please!
How can I change this y=2/3x^(3/2)-1/2x^(1/2) in term of y, as x=...?
How can I change this y=2/3x^(3/2)-1/2x^(1/2) in term of y, as x=...?
I always assume calculator syntax if it's unclear.Originally posted by HallsofIvy
StephenPrivitera was assuming you meant
y= (2/3)x^(3/2)-(1/2)x^(1/2).
What you wrote could as easily be interpreted as
y= 2/(3x^(3/2)-1/(2x^(1/2))).
The equation represents a curve on a graph, where the y-coordinate is equal to 2/3 times the square root of the x-coordinate cubed, minus 1/2 times the square root of the x-coordinate.
To graph the equation, you can plot specific points by choosing values for x and solving for y. You can also use a graphing calculator or online graphing tool to visualize the curve.
Yes, the equation can be simplified to y=x^(1/2)(2/3x-1/2), which may make it easier to graph or manipulate.
To find the x-intercepts, set y=0 and solve for x. In this case, you will have two solutions, one at x=0 and one at x=9/4.
The domain of the equation is all real numbers greater than or equal to 0. The range is all real numbers greater than or equal to -0.5.