How can I find the coefficient of x^12 in:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] (2+x)^{14}(1+ \frac{2}{x})^{14} [/tex]

I did it like that:

[tex] (2+x)^{14}(1+ \frac{2}{x})^{14} [/tex]

Can be written as:

[tex] (4+ \frac{4+x^2}{x})^{14} [/tex]

Now the term [tex]T_{r+1}[/tex] can be represented as:

[tex] 14C_r (4)^{14-r}(\frac{4+x^2}{x})^r[/tex] (How can I write 14Cr?)

Dont know where to go from here?

Thanks in advance for any help.

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# How can I find the coefficient of x^12

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