- #1
DeathKnight
- 73
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How can I find the coefficient of x^12 in:
[tex] (2+x)^{14}(1+ \frac{2}{x})^{14} [/tex]
I did it like that:
[tex] (2+x)^{14}(1+ \frac{2}{x})^{14} [/tex]
Can be written as:
[tex] (4+ \frac{4+x^2}{x})^{14} [/tex]
Now the term [tex]T_{r+1}[/tex] can be represented as:
[tex] 14C_r (4)^{14-r}(\frac{4+x^2}{x})^r[/tex] (How can I write 14Cr?)
Dont know where to go from here?
Thanks in advance for any help.
[tex] (2+x)^{14}(1+ \frac{2}{x})^{14} [/tex]
I did it like that:
[tex] (2+x)^{14}(1+ \frac{2}{x})^{14} [/tex]
Can be written as:
[tex] (4+ \frac{4+x^2}{x})^{14} [/tex]
Now the term [tex]T_{r+1}[/tex] can be represented as:
[tex] 14C_r (4)^{14-r}(\frac{4+x^2}{x})^r[/tex] (How can I write 14Cr?)
Dont know where to go from here?
Thanks in advance for any help.
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