- #1

mathelord

- Thread starter mathelord
- Start date

- #1

mathelord

- #2

- 208

- 0

area of a triangle is given by 1/2 * b * h

- #3

- 29

- 0

I think mathelord means any three curves. You can use a double integral. Do you know calculus?

- #4

- 1,425

- 1

If you don't know calculus you calculate the height. The factor of two perpendicular slopes is -1.

- #5

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 961

Exactly how that is done depends on the curves themselves. In the very common situation, a sort of "curvy" triangle, where you have one curve under the other two (between the points where the other two intersect it), then you don't need a double integral. You will need to break the integral into two parts. I'm going to call the curve on the bottom C1, the graph of y= f1(x), and the other two C1 and C2, graphs of y=f2(x), y= f3(x) respectively. Let's say that C2 intersect C1 at x=a, C3 intersects C1 at x= c, and that C2 is below C3 until they intersect at x= b after which C3 is below C2.

Then the area is given by two separate integrals:

[tex]\int_a^b(f2(x)-f1(x))dx+ \int_b^c(f3(x)-f1(x)dx[/tex]

- Last Post

- Replies
- 1

- Views
- 552

- Last Post

- Replies
- 9

- Views
- 12K

- Replies
- 16

- Views
- 12K

- Last Post

- Replies
- 2

- Views
- 2K

- Replies
- 3

- Views
- 4K

- Last Post

- Replies
- 5

- Views
- 3K

- Replies
- 22

- Views
- 2K

- Replies
- 8

- Views
- 5K

- Replies
- 6

- Views
- 10K

- Replies
- 2

- Views
- 2K