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**how can this be average force ???**

The short of the question, is which puts the most tension on the muscles ???

Some people say, that if you lift a weight, as in weightlifting/bodybuilding. Slow repetition, up 1m and down 1m, one time at 3 seconds up and 3 seconds down, and let’s call it a 100 pounds. And then with the same weight, fast repetition, for same distance, but up in .5 of a second, and down in .5 of a second, 6 times = 6 seconds as well, that the average forces thus tensions on the muscles are the same in the long run.

HOWEVER, I cannot see this.

Fast and slow repetition/s, {split up into 5 segments, concentric only} 100, 100, 100, 80, 20. {Second fast rep 140, 100, 100, 60, zero} Slow rep, 80, 80, 80, 80, 80. The averages are/seem the same, but the peak forces are higher. That is a rough estimate.

But let’s now do a thought experiment.

You position a piece of clay in-between the fast and slow lifters hands and the barbell, and if you than take the clay out of both lifters, I would say the faster repetition would have flattened the clay out as much as 3 times that of the slow lifter.

But how can that be if the average forces are the same, as when the bar is decelerating on the faster repetition, and not using much force, the slow rep are still using their medium force, thus they should catch up and flatten out the clay as much as the fast reps, but they do not do they ???

THEREFORE, does that mean the average forces are NOT the same.

I say the average forces cannot be the same, as the high higher forces, and the higher peak forces, {peak forces, the forces on the second and conceding repetitions, as of the transition from eccentric to concentric} are far greater total force.

100 = 20, or 25% more than 80, and again, 100 = 20 or 25% more than 80, and again, 100 = 20 or 25% more than 80. Or second rep, 140 = 60 or 75% more than 100, then 100 = 20, or 25% more than 80, and again, 100 = 20 or 25% more than 80, thus I cannot see how the forces are the same. And impulse is higher.

Wayne