# How did this rewrite happen?

## Homework Statement

this is the last step to a laplace transform, but i'm stuck..
$$\frac{(3-2x)}{((s+3)2)+4}$$
to
-2$$\frac{(s+3)}{(((s+3)2)+4)}$$9/2 $$\frac{2}{((s+3)2)+4}$$

thanks

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(use ^ not SUP in LaTeX )

$$\frac{(3-2s)}{((s+3)^2)+4}$$

= $$\frac{(9 - 6 - 2s)}{((s+3)^2)+4}$$

= -2$$\frac{(s+3)}{(((s+3)^2+4)}$$ + 9/2 $$\frac{2}{((s+3)^2)+4}$$