Calculating the Height of a Frictionless Loop Launch

In summary, the conversation discusses the use of an energy equation to determine the height from which a 75 Kg ball bearing was released in a "frictionless" loop. The ball bearing has a diameter of 0.075m and is traveling at 1.9m/s. The force related to gravity is 0.74N and the energy equation involves changes in kinetic energy, kinetic rotational energy, and potential energy. The conversation concludes with a thank you for the explanation.
  • #1
True__Fiction
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At the top of a "frictionless" loop that is 75 cm high, a 75 Kg ball bearing is traveling at 1.9m/s. From what height was the ball released?


I have absolutely no Idea where to start here.

Diameter= 0.075m
Velocity=1.9m/s
Force related to Gravity=0.74N
m=0.075Kg
 
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  • #2


If you are using energy like your tag suggests then write out your energy equation:

ΔE = ΔKv + ΔKr + ΔEtherm + ΔUpot

Etherm can be neglected because the loop is frictionless. Substitute in your energy equations for your change in kinetic energy (HINT ball is assumed to start from rest unless the question otherwise states), the change in kinetic rotational energy (HINT that of a point mass) and your change in potential energy (which will have an unknown value). Solve for unknown and you should get your answer...
 
  • #3


That makes much more sense, THANK YOU
 

1. How do you calculate the height of a frictionless loop launch?

To calculate the height of a frictionless loop launch, you will need to use the conservation of energy principle. This means that the total energy at the start of the launch, which is the potential energy of the object at its maximum height and the kinetic energy of the object at its launch velocity, will be equal to the total energy at the end of the launch, which is the potential energy at the bottom of the loop and the kinetic energy at the top of the loop.

2. What is the equation for calculating the height of a frictionless loop launch?

The equation for calculating the height of a frictionless loop launch is h = (v^2)/(2g), where h is the height of the loop, v is the launch velocity of the object, and g is the acceleration due to gravity. This equation is derived from the conservation of energy principle mentioned before.

3. How does the launch velocity affect the height of a frictionless loop launch?

The launch velocity directly affects the height of a frictionless loop launch. According to the equation mentioned earlier, the height of the loop is directly proportional to the square of the launch velocity. This means that the higher the launch velocity, the higher the height of the loop will be.

4. What other factors can affect the height of a frictionless loop launch?

Apart from the launch velocity, the height of a frictionless loop launch can also be affected by the mass of the object being launched and the radius of the loop. A heavier object will require more energy to reach the top of the loop, resulting in a lower height, while a larger loop radius will require less energy and therefore result in a higher height.

5. Can the height of a frictionless loop launch be greater than the initial height?

Yes, the height of a frictionless loop launch can be greater than the initial height. This is because the initial height only refers to the maximum height of the object before it starts its launch, while the height of the loop takes into account the additional height gained from the launch itself. As long as the launch velocity is high enough, the object can reach a greater height at the top of the loop.

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