A rocket is launched with an initial velocity of 75.0 m/s [53 degreess above the horizontal]. It goes for 25.0 s along its initial line of motion with an overall acceleration of 25 m/s^2. At this time the rockets fail and the rocket follows a projectile path. Find the total time, dy, and dx, in no particular order.(adsbygoogle = window.adsbygoogle || []).push({});

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so would the vx and vy be:

vx=700cos53 m/s

vy=700sin53 m/s

(700 is the vf of the rocket after 25.0 s, before getting into a projectile path; so is it correct to assume that 700 is the vi for the projectile?)

And so far I've come up with dy = tan θ + ½ a (dx/ Vicosθ)^2... I really don't know what to do next...

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# How do I go about this [projectile motion]

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