Given equation(adsbygoogle = window.adsbygoogle || []).push({});

f(x) = x^4 + 4x^3 - 2

so f ' (x) = 4x^3 + 12x^2

which simplified to

f ' (x) = 4x^2 (x+3), thus our critical points are 0 and -3

I will use this to sketch the curve

f ' (x) = 4x^2 (x+3)

Results are below.

According to my "sketch", the sequence is - , +, +, +

B means "before"

A means "after"

I used a very close number to generate this list

But I could not generate any sketch because (0,0) pair cannot have a +, +, + sequence. There must be a - sign, meaning the correct sequence should be -, +, -, +.

I need to hite (0,0) but there is no way as (-3,0) is increasing.

My calculator shows a different sequence. What is wrong with my sketch logic here?

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# How do I graph this?

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