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How do i integrate this?

  1. Apr 12, 2009 #1
    how do i integrate this??

    how do i integrate this function?

    [tex]\int[/tex]dx/(ex-1)0.5

    i have tried all the methods i know and havent cracked it, the best try i have had so far is

    [tex]\int[/tex]dx/(ex-1)0.5

    ===>t=ex; dt=exdx

    [tex]\int[/tex]dt/t*([tex]\sqrt{t-1}[/tex])

    now from here i tried integration in parts and got really complicated

    u=1/[tex]\sqrt{t-1}[/tex]
    du=-dt/2(t-1)1.5

    dv=dt/t
    v=ln(t)

    =[tex]\int[/tex]dt/t*[tex]\sqrt{t-1}[/tex]=ln(t)/[tex]\sqrt{t-1}[/tex]-[tex]\int[/tex]-ln(t)dt/2(t-1)1.5

    how else can i solve this
     
    Last edited: Apr 12, 2009
  2. jcsd
  3. Apr 12, 2009 #2
    Re: how do i integrate this??

    http://integrals.wolfram.com/index.jsp?expr=(e^x-1)^-0.5&random=false

    Integrals are hard
     
  4. Apr 12, 2009 #3
    Re: how do i integrate this??

    Use the substitution t=sqrt(exp(x)-1) => x=ln(t^2+1)
     
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