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How do I solve for theta

  1. Nov 21, 2009 #1
    1. The problem statement, all variables and given/known data

    How do I solve for theta here:

    √13 Sin(θ-56.31)=1 in the interval 0< θ <360

    2. The attempt at a solution
    sin (θ - 56.31) = 1/√13
    sin (θ - 56.31) = sin ( 16.102 )
    => θ - 56.31 = 16.102
    Hence θ = 72.412
    or θ - 56.31 = 180 - 16.102
    θ - 56.31 = 163.898
     
  2. jcsd
  3. Nov 21, 2009 #2

    Mentallic

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    Homework Helper

    Re: Trigonometry

    Yes that's correct. You had one line left to go, why did you stop? :tongue2:

    And this is assuming there is an interval for [itex]\theta[/itex] such as [itex]0<\theta<360^o[/itex] because then you'll have an infinite number of solutions.
     
  4. Nov 22, 2009 #3
    Re: Trigonometry

    yes, there are an infinite number of solutions. Think about the periot of sine.
    for example, f(x+2*pi)=f(x)
    ...f(30+(-360))=f(30)=f(30+360)=f(30+720)=....
     
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