Homework Help: How do I solve for theta

1. Nov 21, 2009

MorallyObtuse

1. The problem statement, all variables and given/known data

How do I solve for theta here:

√13 Sin(θ-56.31)=1 in the interval 0< θ <360

2. The attempt at a solution
sin (θ - 56.31) = 1/√13
sin (θ - 56.31) = sin ( 16.102 )
=> θ - 56.31 = 16.102
Hence θ = 72.412
or θ - 56.31 = 180 - 16.102
θ - 56.31 = 163.898

2. Nov 21, 2009

Mentallic

Re: Trigonometry

Yes that's correct. You had one line left to go, why did you stop? :tongue2:

And this is assuming there is an interval for $\theta$ such as $0<\theta<360^o$ because then you'll have an infinite number of solutions.

3. Nov 22, 2009

nalkapo

Re: Trigonometry

yes, there are an infinite number of solutions. Think about the periot of sine.
for example, f(x+2*pi)=f(x)
...f(30+(-360))=f(30)=f(30+360)=f(30+720)=....