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[itex]\displaystyle\lim_{x\rightarrow \infty} {\frac{3x+5}{x-4}}[/itex]

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[itex]\displaystyle\lim_{x\rightarrow \infty} {\frac{3x+5}{x-4}}[/itex]

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I worked it out. Never mind.

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HallsofIvy

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[tex]\lim_{x\to\infty} \frac{3x+ 5}{x- 4}= \frac{3+ \frac{5}{x}}{1- \frac{4}{x}}[/tex]

Now, as x goes to infinity, the terms with x in the denominator go to 0.

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