# How Do I Solve These Angular Speed Physics Problems?

• Nanabit
In summary, there are a few problems being discussed. The first involves finding the coefficient of kinetic friction between a potters wheel and a wet rag. The second problem involves determining the speeds of two masses suspended by a pulley. The third problem involves using energy principles to find the angular speed of a grindstone after a certain number of revolutions. And the fourth problem involves using kinematics and energy principles to find the time and number of revolutions it takes for a grinding wheel to reach a certain rotational speed.
Nanabit
I have a couple problems that I have started but don't quite know where to go with them. If someone could respond ASAP it would be greatly appreciated as one of them will probably appear on a test tomorrow :) Thanks!

1) A potters wheel (a thick stone disk with a radius of .500 m and a mass of 100 kg) is freely rotating at 50.0 rev/min. The potter can stop the wheel in 6.00 sec by pressing a wet rag against the rim and exerting a radial force of 70.0 N. Find the effective coefficient of kinetic friction between the wheel and the rag.

Alright, I know you have to convert 50 rev/min to rev/sec to get omega initial. I also know the sum of torque is Fd or Ialpha. I can figure out both I and alpha. d I'm figuring is the radius. But the problem is, if F is the coefficient times the normal force, I don't even need that? But it doesn't work out anyway?

2) A mass 15.0 kg and a mass 10.0 kg are suspended by a pulley that has a radius 10.0 cm and a mass 3.0 kg. The cord has a negligible mass and causes the pulley to rotate without slipping. The masses start from rest a distance 3.00 m apart. Treating the pulley as a uniform disk, determine the speeds of the two masses as they pass each other.

Alright, so once again torque = Ialpha. I can get I. alpha I'm not quite sure .. I played with kinematics but all of them require either time or theta. I don't know where to go when I get torque though.

3) A constant torque of 25.0 Nm is applied to a grindstone whose moment of inertia is .130kgm^2. Using energy principles, find the angular speed after the grindstone has made 15.0 revolutions (neglect friction).

Alright, by using torque = Ialpha I got alpha to be 192 rad/sec^2. However, since I don't know what the initial angular speed was and don't have a time, I couldn't find a kinematic to use.

4) A grinding wheel is in the form of a uniform solid disk having radius of 7.00 cm and a mass of 2.00 kg. It starts from rest and accelerates uniformly under the action of the constant torque of .600 Nm that the motor exerts on the wheel. (a) How long does it take the week to reach its final rotational speed of 1200 rev//min? (b) Through how many revolutions does it turn while accelerating?

Once again, a kinematic problem. I figure you can get I from formulas and thus find alpha.
I = (1/2)MR^2
torque = Ialpha
omegaf = omegai + alpha time
20 = o +(122)t
t = .163 sec

But t = 1.03 sec. If I can get that then I can get part b.

1. a. Use kinematics to find what value of acceleration will slow a wheel down from &omega;o to 0 in 6 seconds. (Convert rev/min to rad/s, not rev/s)
b. Compute the inertia of the wheel. Assume a uniform mass distribution. You should look up the derivation (it's not hard), but you'll find that I = .5*M*r^2
c. The only torque about the center of the wheel is caused by the friction and has a value of f*r, where f = &mu;N, and N is the force applied by the person on the stone. Set this equal to I&alpha; where &alpha; is the acceleration found in part a.

2. &alpha; is the unknown here. Find the sum of torques about the center of the pulley (it will equal the difference in weights times the radius). Take care in establishing a sign convention. Solve for &alpha; using &tau;net = I&alpha; You can then convert &alpha into the linear acceleration of each of the masses (note that the geometric constraint of the rope requires that the velocity of the two masses be equal in magnitude). Knowing the constant acceleration, initial positions, and the fact that the system starts at rest, you should be able to find the answer that is being looked for.

3. Here, you're asked to use energy principles. Assuming the wheel starts at rest, you need to apply the work-energy theorem. Because the applied torque is constant, the work done by this torque is given by &tau;&Delta;&theta;, where &tau; is the torque and &Delta;&theta; is the angle the wheel turns through under that torque. Set the work done equal to the change in kinetic energy, where kinetic energy of an object in pure rotation is given by .5*I*&omega;^2

4. If you convert rev/min into rad/s properly and repeat what you tried to do, you will get the right answer.

Hi there! It looks like you have a good understanding of the concepts involved in these problems, but may just need a little guidance on how to approach them. Here are some tips that may help:

1) For the first problem, you are correct in using the equation torque = I*alpha. To find the effective coefficient of kinetic friction, you will also need to use the equation F = mu * N, where N is the normal force and F is the radial force exerted by the potter. Remember that the normal force is equal to the weight of the wheel, which can be calculated using the mass and the acceleration due to gravity.

2) In the second problem, you can use the equation torque = I*alpha to find the angular acceleration of the pulley. Since the pulley is rotating without slipping, the linear acceleration of the masses will be equal to the angular acceleration of the pulley multiplied by the radius of the pulley. From there, you can use kinematics equations to find the speeds of the masses as they pass each other.

3) In the third problem, you are correct in using the equation torque = I*alpha to find the angular acceleration. To use energy principles, you can use the equation KE = (1/2)*I*omega^2 to find the kinetic energy of the grindstone after it has made 15 revolutions. Since the grindstone starts from rest, the initial kinetic energy will be zero. Setting the final kinetic energy equal to the initial potential energy (which can be calculated using the weight and height of the grindstone), you can solve for the final angular speed.

4) For the fourth problem, you can use the equation torque = I*alpha to find the angular acceleration. Once you have the angular acceleration, you can use kinematics equations to find the time it takes for the wheel to reach its final rotational speed. To find the number of revolutions, you can use the equation theta = (1/2)*alpha*t^2, where theta is the total angle rotated and t is the time it takes to reach that angle.

I hope this helps! Remember to always carefully read and understand the given information in the problem, and use the relevant equations to solve for the unknowns. Best of luck on your test tomorrow!

## 1. What is angular speed?

Angular speed is a measure of how fast an object is rotating around an axis, usually measured in radians per second.

## 2. How is angular speed different from linear speed?

Linear speed measures how fast an object is moving in a straight line, while angular speed measures how fast an object is rotating around an axis.

## 3. What is the formula for calculating angular speed?

The formula for angular speed is ω = θ/t, where ω is the angular speed, θ is the angular displacement, and t is the time taken.

## 4. How is angular speed related to angular velocity?

Angular speed and angular velocity are closely related, as they both measure the rotation of an object. However, angular velocity also takes into account the direction of rotation, while angular speed only measures the magnitude.

## 5. How does angular speed affect centripetal acceleration?

Angular speed and centripetal acceleration are directly related, as an increase in angular speed will result in a higher centripetal acceleration, and vice versa. This is because centripetal acceleration is caused by a change in the direction of velocity, which is affected by angular speed.

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