Why Does Calculating Runner A's Distance Give Different Results?

[deaninator]

Homework Statement

Runner A runs at 6.0 m/s for 10 s. How far does he go?
NOTE: THE ANSWER IS 60 m BUT I DON'T KNOW HOW IT GOT TO THAT.

Homework Equations

V=Vo + at
X=1/2(Vo +V)T
X=VoT + 1/2at2
V2=Vo2 + 2ax

(If a 2 is after a letter then it means squared)
X=displacement
A=Acceleration
T=Tome
Vo=Initial Velocity
V=Velocity

The Attempt at a Solution

X=1/2(Vo +V)T
x=1/2(6 m/s)(10 sec)

 

[fss]

You have a velocity (m/s) and a time (s). Even just looking at the units, how would you get a distance (m) ?

 

[deaninator]

You have a velocity (m/s) and a time (s). Even just looking at the units, how would you get a distance (m) ?

You get the distance using the distance formula that I have listed above under previous tries...

 

[dickface]

lol poor attempt at trolling tbh.

 

[rwisz]

[Plug in the given values]
x=1/2(60 m)
x=30 m [Simplify]

The key to solving this kinematic problem is to use the correct equation that relates the variables given in the problem. In this case, we are given the initial velocity (Vo), time (T), and want to find the displacement (X). The equation that relates these variables is X=1/2(Vo +V)T.

To solve, simply plug in the given values and simplify the equation. In this case, the initial velocity (Vo) is 6.0 m/s and the time (T) is 10 seconds. Plugging these values into the equation, we get X=1/2(6 m/s)(10 sec), which simplifies to X=30 m. This means that Runner A traveled a distance of 30 meters in 10 seconds at a velocity of 6.0 m/s.

It is important to note that there are other equations that can also be used to solve this problem, such as X=VoT + 1/2at^2 or V^2=Vo^2 + 2aX. These equations may be more suitable depending on the given variables and the information that is being asked for. It is always important to carefully read the problem and determine which equation to use before plugging in values.