A grasshopper jumps 1.00 m from rest, with an initial velocity at a 45.0 degree angle with respect to the horizontal. Find a. the initial speed of the grasshopper (the answer is 3.13 m/s) and b. the maximum height reached ( the answer is .250 meters).
V naught of x= v naught (hyp. of v. vectors) times cos (projection angle)
It should all be derived from the basic mechanic equations;
V= vnaught times time + a times time
Delta x= vnaught times time + .5 a times time squared
v squared= v naught squared + 2a delta x
I suspect they want me to use the cosine and sine versions but I need the steps so I can truly understand what I'm looking for!
The Attempt at a Solution
I keep getting zero I don't understand
Can somebody please give me all the steps for this problem and what formulas to use if I don't have them. I can crunch the numbers but for some reason I have a mental block on this problem. I don't even get how if it starts at rest, it can have any other value but zero.