A dive bomber has a velocity of 275 m/s at an angle (theta) below the horizontal. When the altitude of the aircraft is 2.15 km, it releases a bomb, which subsequently hits a target on the ground. The magnitude of the displacement from the point of release of the bomb to the target is 3.45 km. Find the angle (theta). OK, i'm not seeing a way to solve this without being given the time (t) it took for it to hit the ground, am i missing something here?