# How do int. 1/(4-11x^2)^2 ?

1. Feb 29, 2004

### Matt Jacques

How do integrate 1/(4-11x^2)^2 ?

It looks like partial fractions, but how do I do it when there is (a+bx^2)^2?

I know it is something like

1/(4-11x^2)^2 = Ax + b / (4-11x^2)^2

2. Feb 29, 2004

### HallsofIvy

Staff Emeritus
Then, as is often the case with posts like this, you know incorrectly. 1 over a polynomial is NOT "Ax+ anything"!
$$\frac{1}{(4-11x^2)^2}= \frac{A}{2-\sqrt{11}x}+ \frac{B}{(2-\sqrt{11}x)^2}+ \frac{C}{2+\sqrt{11}x}+ \frac{D}{(2+\sqrt{11}x)^2}$$