- #1
xyz_1965
- 76
- 0
Compute the area of the shaded segment of a circle. A segment of a circle is a region bounded by an arc of the circle and its chord. The radius r is given to be 3 cm and the central angle theta is 120°. Give two forms for the answer: an exact expression and a calculator approximation rounded to two decimal places.
Use: area of segment = (area of sector OPQ) - (area of triangle OPQ).
Area of sector OPQ = (1/2)r^2(theta).
Area of triangle OPQ = (ab/2)(sin (theta)).
Solution:
Central angle is theta.
= 120°
= 2•pi/3 rad
Area of the shaded segment
= (Area of the sector) - (Area of the triangle)
= [(1/2) × 3^2 × (2•pi/3) - (1/2) × 3^2 × sin(120°)] cm^2
= [3•pi - (9/2) × sin(180° - 60°)] cm^2
= [3•pi - (9/2) × sin(60°)] cm^2
= [3•pi - (9/2) × (sqrt{3}/2)] cm^2
= [3•pi - (9/4)sqrt{3}] cm^2
= (3/4)[4•pi - 3sqrt{3}] cm^2
= 5.53 cm^2
You say?
Note: All work is done on paper prior to posting.
Use: area of segment = (area of sector OPQ) - (area of triangle OPQ).
Area of sector OPQ = (1/2)r^2(theta).
Area of triangle OPQ = (ab/2)(sin (theta)).
Solution:
Central angle is theta.
= 120°
= 2•pi/3 rad
Area of the shaded segment
= (Area of the sector) - (Area of the triangle)
= [(1/2) × 3^2 × (2•pi/3) - (1/2) × 3^2 × sin(120°)] cm^2
= [3•pi - (9/2) × sin(180° - 60°)] cm^2
= [3•pi - (9/2) × sin(60°)] cm^2
= [3•pi - (9/2) × (sqrt{3}/2)] cm^2
= [3•pi - (9/4)sqrt{3}] cm^2
= (3/4)[4•pi - 3sqrt{3}] cm^2
= 5.53 cm^2
You say?
Note: All work is done on paper prior to posting.