How Do You Calculate the Mole Fraction of NaCl in a Solution?

  • Thread starter Integral0
  • Start date
  • Tags
    Vapor
In summary, the conversation is about finding the mole fraction of NaCl in a solution of sodium chloride in water that has a vapor pressure of 19.6 torr at 25 degrees celsius. The mole fraction of H20 is calculated to be 0.824 using Raoult's Law, and the question is how to find the mole fraction of the solute (NaCl). The answer is that the mole fraction of water is equal to the mole fraction of solute, and therefore the mole fraction of NaCl is also 0.824. This is because ionic solutes, such as NaCl, dissolve into their constituent ions, so the mole ratio of NaCl to water is 1:1.
  • #1
Integral0
49
0
Here is the question:

A solution of sodium chloride in water has a vapor pressure of 19.6 torr at 25 degrees celsius. What is the mole fraction of NaCl in this solution? The vapor pressure of pure water is 23.8 torr at 25 degrees celsius.
---------------------------------------------------------------
Here's what I need help with:

I am able to determine the mole fraction for H20 = .824
because I took Psoln = XsolventP^0solvent (Raoult's Law) and then I did this

Psoln divided by P^0solvent to get Xsolvent (kie solvent(mole fraction of solvent or H20)).

I got .824 for the mole fraction of H20 but now I am unsure about how to find the mole fraction of the solute (NaCl).

HOW DO YOU FIND THE MOLE FRACTION OF THE SOLUTE?

Thanks
 
Chemistry news on Phys.org
  • #2
1 - mole fraction of water = mole fraction of solute.
 
Last edited:
  • #3
RE;

How did you formulate this, GeneralChemtutor?

Does that mean .824 H20 solvent = .824 NaCl solute?

----------------------------------------------------------

If this is true . . . doesn't it need to be 2(.824)? B/c ionic solute's dissolve . . . like this -> NaCl -> 1 mol Na + 1 mol Cl ??
 
Last edited:
  • #4
Back
Top