# How Do You Calculate the Requirements for a Steam Plant Using Waste Gas Heating?

• vvexor
In summary, the required mass of wast gas is 6495 kg/hr and the temperatures of the gasses leaving the evaporator, superheater, and economizer are 617.2°C, 782.6°C, and 824.2°C, respectively. The temperature of the water leaving the economizer is 689.6°C.
vvexor
I desperately need help with a equation. During a planning stage of a steam plant it was determent that 21 650 kg steam per hour at a pressure of 0.5 MPa and a temperature of 200 deg C were required.The available feed water temperature is 34,6 deg C.The efficiency of the plant is 70% and wast gasses will be used for the heating of the plant the temperature of the gasses is 760 deg C while the atmospheric temp is 15 deg C

Calculate
a)the mass of wast gas required
b)the temperature of the gasses
1)leaving the evaporator
2)leaving the superheater
3)leaving the economizer
c)temp of water leaving the economizer

Last edited:
! a) The mass of wast gas required can be calculated using the formula:Mass of Wast Gas = Mass of Steam x (1 - Efficiency) Mass of Wast Gas = 21 650 kg/hr x (1 - 0.7) Mass of Wast Gas = 6495 kg/hr b)The temperature of the gasses leaving the evaporator, superheater, and economizer can be calculated using the following formulas:Evaporator Exit Temperature = Feed Water Temperature + (Wast Gas Temperature - Atmospheric Temperature) x Efficiency Evaporator Exit Temperature = 34.6°C + (760°C - 15°C) x 0.7 Evaporator Exit Temperature = 617.2°C Superheater Exit Temperature = Evaporator Exit Temperature + (Required Steam Temperature - Feed Water Temperature) Superheater Exit Temperature = 617.2°C + (200°C - 34.6°C) Superheater Exit Temperature = 782.6°C Economizer Exit Temperature = Superheater Exit Temperature + (Wast Gas Temperature - Atmospheric Temperature) x (1 - Efficiency) Economizer Exit Temperature = 782.6°C + (760°C - 15°C) x (1 - 0.7) Economizer Exit Temperature = 824.2°C c) The temperature of the water leaving the economizer can be calculated using the following formula:Water Exit Temperature = Economizer Exit Temperature - (Required Steam Temperature - Feed Water Temperature) Water Exit Temperature = 824.2°C - (200°C - 34.6°C) Water Exit Temperature = 689.6°C

- m: mass of steam required per hour (21,650 kg)
- P: pressure (0.5 MPa)
- T: temperature (200°C)
- Tfw: feed water temperature (34.6°C)
- η: efficiency of the plant (70%)
- Tg: temperature of waste gases (760°C)
- T0: atmospheric temperature (15°C)

Now, we can use the following equations to calculate the required information:

a) Mass of waste gas required:
Since the efficiency of the plant is 70%, we can use the equation: m = msteam / η
Substituting the values, we get:
m = (21,650 kg/hr) / 0.70 = 30,929 kg/hr

b) Temperature of gases leaving the evaporator:
We can use the formula for ideal gas law: P1V1/T1 = P2V2/T2
Since the waste gases are used for heating, the volume remains constant (V1 = V2). Therefore, we can rearrange the equation to find T2:
T2 = (P2/P1) * T1
Substituting the values, we get:
T2 = (0.5 MPa/101.325 kPa) * (760°C + 273.15) = 4,248.6°C

Temperature of gases leaving the superheater:
To find the temperature of gases leaving the superheater, we can use the same equation as above, but with the new pressure and temperature values:
T2 = (0.5 MPa/101.325 kPa) * (200°C + 273.15) = 972.4°C

Temperature of gases leaving the economizer:
To find the temperature of gases leaving the economizer, we need to use the energy balance equation:
msteam * Hsteam = mgas * Hgas + mwater * Hwater
where H represents enthalpy. We can rearrange this equation to find the temperature of gases leaving the economizer:
Tgas = (msteam * Hsteam - mwater * Hwater) / (mgas * Cpgas)
where Cpgas is the specific heat of the waste gases. Substituting the values, we get:
Tgas = [(21,

## 1. What is a Calc Steam Plant?

A Calc Steam Plant is a power plant that uses a process called calcination to produce steam. Calcination involves heating a material, such as limestone, to high temperatures to drive off carbon dioxide, resulting in a material called quicklime. The quicklime is then mixed with water to produce steam, which can be used to power turbines and generate electricity.

## 2. What are the requirements for a Calc Steam Plant?

The requirements for a Calc Steam Plant include a source of raw materials, such as limestone, a high-temperature furnace, a steam turbine, and a cooling system. The plant also needs a steady supply of water, fuel, and electricity to operate efficiently.

## 3. How does a Calc Steam Plant impact the environment?

Like all power plants, a Calc Steam Plant can have both positive and negative impacts on the environment. On the positive side, it produces clean energy and reduces the reliance on fossil fuels. However, the high temperatures used in the calcination process can release pollutants into the air, and the plant's cooling system can also have a negative impact on aquatic life if not properly designed and managed.

## 4. What are the benefits of using a Calc Steam Plant?

There are several benefits to using a Calc Steam Plant. First, it is a renewable and sustainable source of energy, as long as there is a steady supply of raw materials. It also produces low-emission electricity, making it a more environmentally friendly option compared to fossil fuel power plants. Additionally, the byproduct of the calcination process, quicklime, can be used in various industries, such as construction and agriculture.

## 5. Are there any safety concerns with a Calc Steam Plant?

As with any industrial facility, there are safety concerns with a Calc Steam Plant. The high temperatures and pressures involved in the process can pose risks to workers, and proper safety protocols and equipment must be in place to prevent accidents. There is also a risk of air and water pollution if the plant is not properly designed and operated. Regular maintenance and inspections are essential to ensure the safety and efficiency of a Calc Steam Plant.

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