How do you derive this? SImple question

  • Thread starter Alipepsi
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  • #1
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Derive for time!
D=Vit+1/2at^2

THANKS for you help
 

Answers and Replies

  • #2
2,967
5
The displacement is given by the area under the velocity-time graph. Your velocity-time equation is:
[tex]
v(t) = v_i + a t
[/tex]
and between the vertical lines [itex]t_1 = 0[/itex] and [itex]t_2 = t[/itex]. The geometric figure is a right trapezoid (trapzium outside U.S.) and the area is:
[tex]
D = \frac{1}{2} \left[ v_i + (v_i + a \, t) \right] \cdot t = v_i \, t + \frac{a \, t^2}{2}
[/tex]
 

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