1. Feb 1, 2015 #1

   lola2000

   

   1. The problem statement, all variables and given/known data
   I am not sure how to graph the function
   
   f(x)=(x+p)+q
   
   2. Relevant equations
   
   
   3. The attempt at a solution
   
   When x=0 y=p+q
   if y=0 x=-q-p ???
   
   what shape would this give??

    

   lola2000, Feb 1, 2015
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3. Feb 1, 2015 #2

   siddharth23

   

   f(x) = (x + p) + q can also be written as f(x) = x + (p + q)
   No as p and q are both constants, let:
   p + q = c
   Sp, we get f(x) = x + c
   This is similar to the equation y = mx + c. What does this equation stand for?

    

   siddharth23, Feb 1, 2015
4. Feb 1, 2015 #3

   lola2000

   

   
   So it will just be a straight line upwards with a gradient of 1 and y intercept of p+q?

    

   lola2000, Feb 1, 2015
5. Feb 1, 2015 #4

   Mark44

   

   Insights Author

   Staff: Mentor

   This is nothing more than a straight line whose slope is 1 and whose y-intercept is p + q.
   
   The only reason I can think of for writing the right side as (x + p) + q is to get you to recognize this as a horizontal translation and a vertical translation of the graph of y = x.

    

   Mark44, Feb 1, 2015
6. Feb 1, 2015 #5

   siddharth23

   

   Yes!

    

   siddharth23, Feb 1, 2015

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