- #1

- 13

- 0

## Homework Statement

I am not sure how to graph the function

f(x)=(x+p)+q

## Homework Equations

## The Attempt at a Solution

When x=0 y=p+q

if y=0 x=-q-p ???

what shape would this give??[/B]

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter lola2000
- Start date

- #1

- 13

- 0

I am not sure how to graph the function

f(x)=(x+p)+q

When x=0 y=p+q

if y=0 x=-q-p ???

what shape would this give??[/B]

- #2

- 249

- 26

f(x) = (x + p) + q can also be written as f(x) = x + (p + q)## Homework Statement

I am not sure how to graph the function

f(x)=(x+p)+q

## Homework Equations

## The Attempt at a Solution

When x=0 y=p+q

if y=0 x=-q-p ???

what shape would this give??[/B]

No as p and q are both constants, let:

p + q = c

Sp, we get f(x) = x + c

This is similar to the equation y = mx + c. What does this equation stand for?

- #3

- 13

- 0

f(x) = (x + p) + q can also be written as f(x) = x + (p + q)

No as p and q are both constants, let:

p + q = c

Sp, we get f(x) = x + c

This is similar to the equation y = mx + c. What does this equation stand for?

So it will just be a straight line upwards with a gradient of 1 and y intercept of p+q?

- #4

Mark44

Mentor

- 35,994

- 7,925

This is nothing more than a straight line whose slope is 1 and whose y-intercept is p + q.lola2000 said:f(x)=(x+p)+q

The only reason I can think of for writing the right side as (x + p) + q is to get you to recognize this as a horizontal translation and a vertical translation of the graph of y = x.

- #5

- 249

- 26

Yes!So it will just be a straight line upwards with a gradient of 1 and y intercept of p+q?

Share: