- #1

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## Homework Statement

I am not sure how to graph the function

f(x)=(x+p)+q

## Homework Equations

## The Attempt at a Solution

When x=0 y=p+q

if y=0 x=-q-p ???

what shape would this give??[/B]

- Thread starter lola2000
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- #1

- 13

- 0

I am not sure how to graph the function

f(x)=(x+p)+q

When x=0 y=p+q

if y=0 x=-q-p ???

what shape would this give??[/B]

- #2

- 249

- 26

f(x) = (x + p) + q can also be written as f(x) = x + (p + q)## Homework Statement

I am not sure how to graph the function

f(x)=(x+p)+q

## Homework Equations

## The Attempt at a Solution

When x=0 y=p+q

if y=0 x=-q-p ???

what shape would this give??[/B]

No as p and q are both constants, let:

p + q = c

Sp, we get f(x) = x + c

This is similar to the equation y = mx + c. What does this equation stand for?

- #3

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f(x) = (x + p) + q can also be written as f(x) = x + (p + q)

No as p and q are both constants, let:

p + q = c

Sp, we get f(x) = x + c

This is similar to the equation y = mx + c. What does this equation stand for?

So it will just be a straight line upwards with a gradient of 1 and y intercept of p+q?

- #4

Mark44

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This is nothing more than a straight line whose slope is 1 and whose y-intercept is p + q.lola2000 said:f(x)=(x+p)+q

The only reason I can think of for writing the right side as (x + p) + q is to get you to recognize this as a horizontal translation and a vertical translation of the graph of y = x.

- #5

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Yes!So it will just be a straight line upwards with a gradient of 1 and y intercept of p+q?

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