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Precalculus Mathematics Homework Help
How do you know how many solutions there are for z?
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[QUOTE="Darkmisc, post: 6636720, member: 229348"] [B]Homework Statement:[/B] z^3+8i=0 [B]Relevant Equations:[/B] r^3cis3t = 8cis(-pi/2) Hi everyone How do you know how many solutions z has a) in this problem b) in general? I understand that they are rotating 2 pi from (-pi/2) in both directions to get the other two solutions. Should this be done in all problems? Is it simply a coincidence that there are three solutions when z is in the third power? If the problem needed to be solved for z^4, would there be four solutions? Or only three (again by rotating 2 pi in both directions)? Thanks[ATTACH type="full"]302018[/ATTACH] [/QUOTE]
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Precalculus Mathematics Homework Help
How do you know how many solutions there are for z?
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