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How do you solve for n in this question 34=r^n

  1. Aug 14, 2005 #1
    how do you solve for n in this question
    34=r^n

    i know what the r value is


    man i should know this
     
    Last edited: Aug 14, 2005
  2. jcsd
  3. Aug 15, 2005 #2

    Fermat

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    take logs
    ========================================================
     
  4. Aug 15, 2005 #3

    HallsofIvy

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    In general the way to "move" a number out of an exponent is to use the inverse of exponential: logarithm. If rn= 34, then n log(r)= log(34) so n= log(34)/log(r). It doesn't matter what logarithme you use: common (base 10) or natural (base e) are on your calculator but any base will do.
     
  5. Aug 15, 2005 #4
    logs: they're better than bad; they're good! :tongue2:
     
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