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How do you square cosB?

  1. Jan 24, 2009 #1
    1. The problem statement, all variables and given/known data


    2. Relevant equations

    how do you square cosB?

    3. The attempt at a solution
  2. jcsd
  3. Jan 24, 2009 #2
    Re: squaring

    Hi chemic_23, well you haven't really asked a question. In answer to you how do you square [itex]cos\beta[/itex] (i assume thats what you meant) you can square it like any other number as [itex]\textbf{cos\beta}[/itex] will be a real number if beta is a real number. Is you question find the solutions to this equation, because there are an infinite number of them?

    If you could clarify you question then Im sure you'll find the help you need :D
  4. Jan 24, 2009 #3
    Re: squaring

    I'm trying to understand this part of solution
    but I don't have any idea on how to square the cosB... It just came out with no detailed solution.... please help
  5. Jan 24, 2009 #4
    Re: squaring

    if you have f(l) = (x + y) / z where x,y,z are constants

    remember you can always change that to

    x /z + y/z

    and then what would be f^2 (l)

    (x /z + y/z)^2 = (x /z + y/z)(x /z + y/z)

    and you can expand that right?
  6. Jan 24, 2009 #5
    Re: squaring

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