(adsbygoogle = window.adsbygoogle || []).push({}); how do you take the natural logs??

I think this is why I can't do my problems, maybe i'm missing some basic concepts.

ok, so let [tex] L({\theta}) = \theta^{-2n} \prod y e^{-(1/theta)}\sum y [/tex]

taking the natural log, I get

[tex]ln L(\theta) = -2nln\theta + ln \prod y - 1/\theta \sum yi [/tex].

I dont know, how did they do that?

and later, I will need to differentate it too, but and I dont know how to do it either. but for that one, how did they do it?

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# Homework Help: How do you take the natural logs?

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