1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

How does a refrigerator work?

  1. Feb 17, 2014 #1
    Hi!

    I wonder how a refridgerator work.

    I understand that the Ideal Gas Law

    [tex]pV=N_{mol}RT[/tex]

    is used somehow.

    This is my blog description of my preliminary understanding:

    "Here both N and V is constant. A compressor on the outside of the refridgerator enables high pressure of the gas there. A high pressure valve then lets some of the gas inside the refridgerator. While the pressure inside then is much lower it absorbs heat to get back to its original pressure before it is circulated back into the system(?)"

    Thankful for any correction.

    Best regards, Roger
     
  2. jcsd
  3. Feb 17, 2014 #2

    ZapperZ

    User Avatar
    Staff Emeritus
    Science Advisor
    Education Advisor
    2016 Award

  4. Feb 17, 2014 #3

    russ_watters

    User Avatar

    Staff: Mentor

    Vapor compression refrigeration: http://en.wikipedia.org/wiki/Vapor-compression_refrigeration

    This is one of those rare cases where I prefer wikipedia to hyperphysics. Besides being thin on the details for heat pumps/air conditioners, it incorrectly defines the term "heat engine" (saying a heat pump is a heat engine, which is basically a self-contradiction).
     
  5. Feb 18, 2014 #4

    sophiecentaur

    User Avatar
    Science Advisor
    Gold Member

    The central part of a refrigeration cycle like this is that the expanding gas / vapour has to Do Work, which will lower its internal energy. The nozzle that the gas is allowed to pass through is the thing that does this work in the 'throttling process'. If the gas were allowed to expand without doing any work, there would be no cooling effect.
     
  6. Feb 18, 2014 #5
    I was wondering, why is it that when we open the refrigirator, we see a 'mist' kind of thing. Is it because of the moisture in the atmosphere condensing when it enters the refrigirator?
     
  7. Feb 18, 2014 #6
    An ideal gas can be used for refrigeration in a four step process.
    1st: The compressor compresses the gas adiabatically. Both pressure and temperature increase.
    2nd: Heat is removed from the gas by bringing it to thermal equilibrium with the outside environment (The kitchen)
    3rd: The air is allowed to expand adiabatically to a low pressure and low temperature.
    4th: Heat is added to the gas by bringing it to thermal equilibrium with the inside environment (heat is removed from the inside of the refrigerator).

    Two Important points.

    1st: Many gases actually used in refrigeration will actually turn liquid when under high pressure, so using ideal gas equations is completely wrong. Latent heat becomes very important.

    2nd: Even for gases, effects such as the Joule–Thomson_effect are very important in most cases. This effect requires treating the gas as a non-ideal gas.
     
  8. Feb 18, 2014 #7
    That's only true for ideal gases. In the real world the Joule–Thomson effect which requires no external work is the main source of cooling. In the throttling process actually used in most refrigeration systems the amount of work actually performed during the expansion is almost negligible.
     
  9. Feb 18, 2014 #8

    russ_watters

    User Avatar

    Staff: Mentor

    Yes.
     
  10. Feb 18, 2014 #9
    Thank you.
     
  11. Feb 19, 2014 #10
    I still think that in common fridges evaporation is the main source of cooling. I even checked Wikipedia.

    High pressure freon flows into low pressure area through a valve which throttles the flow. The freon evaporates, and the pressure of the freon gas decreases.

    My intuition says that evaporation is the main cooling effect there.
     
  12. Feb 19, 2014 #11

    russ_watters

    User Avatar

    Staff: Mentor

  13. Feb 19, 2014 #12

    Andrew Mason

    User Avatar
    Science Advisor
    Homework Helper

    The working fluid does not have to change state, but you have the right idea. Due to strong inter-molecular forces an increase in the separation of molecules will require energy. Since the throttling process is adiabatic and involves no work (free expansion), the only source of this increase in potential energy has to be the internal energy. So molecular kinetic energy has to decrease, hence the temperature decreases.

    AM
     
  14. Feb 19, 2014 #13

    russ_watters

    User Avatar

    Staff: Mentor

    The question wasn't whether it has to or can be done a certain way, it was whether it is done that way. In real refrigeration, the phase change absorbs/releases most of the energy.
     
  15. Feb 19, 2014 #14

    Andrew Mason

    User Avatar
    Science Advisor
    Homework Helper

    Not quite. The phase change of the refrigerant does not absorb heat. The throttling process is adiabatic (no transfer of heat). The absorption of heat from the surroundings occurs AFTER the drop in temperature due to the JT effect as the refrigerant gas comes into thermal contact with the space being cooled.

    AM
     
  16. Feb 20, 2014 #15

    russ_watters

    User Avatar

    Staff: Mentor

    I'm sorry, but you are really making a mess now and it seems trying to nitpick as well. Most of that is wrong:
    1. The phase change in the expansion valve causes latent heat to be converted from sensible heat, dropping the temperature of the fluid as it evaporates:
    2. Then in the evaporator, heat is absorbed from the surroundings and the rest of the liquid evaporates, absorbing more latent heat:
    And:
    For cooling that just uses the Joule-Thompson effect, liquifying gases for cryogenics is one of the few common applications: http://en.wikipedia.org/wiki/Joule–Thomson_effect#Applications
    But notice that this is the opposite of what happens in a refrigerator: the gas expands and cools by the Joule-Thompson effect, causing it to liquify. In a refrigerator, the liquid is throttled and allowed to expand, causing it to vaporize.
     
  17. Feb 20, 2014 #16

    sophiecentaur

    User Avatar
    Science Advisor
    Gold Member

    Also, CO2 from a fire extinguisher causes a change of state as a result of the J-T cooling.
     
  18. Feb 20, 2014 #17

    Andrew Mason

    User Avatar
    Science Advisor
    Homework Helper

    The distinction between evaporative cooling and Joule-Thomson cooling is significant. In evaporative cooling the heat is absorbed from the surroundings during the evaporation process. In JT cooling the energy needed to separate the gas molecules is drawn from the internal kinetic energy of the cooling substance as it is adiabatically throttled. The heat is not absorbed during evaporation. That is the point I was making. I am sorry that you think that is nitpicking or an attempt to mess things up.

    Your point that in a refrigerator there is some evaporative cooling is well taken (the liquid portion of the refrigerant that remains after throttling may evaporate during the heat exchange process).

    AM
     
    Last edited: Feb 20, 2014
  19. Feb 26, 2014 #18
    Hi!

    I have thought some more regarding how a refrigerator might work.

    I have read all your nice explanations but the most important part of understanding came from my collegue.

    Now I only need to know how a compressor actually works. At least I think so.

    Anyway, I am attaching a drawing of my current understanding.

    Best regards, Roger
     

    Attached Files:

  20. Feb 26, 2014 #19

    russ_watters

    User Avatar

    Staff: Mentor

    Still a lot you aren't getting, roger:
    1. A compressor increases pressure to move/circulate the fluid.
    2. The valve creates a pressure drop.
    3. The fluid isn't always a gas, it switches back and forth between gas and liquid.

    Have you not looked at any of the links/information provided?
     
  21. Feb 26, 2014 #20

    Andrew Mason

    User Avatar
    Science Advisor
    Homework Helper

    You have it backwards. The compressor heats up the fluid. This is simply the first law: Q = ΔU + W where W = work done BY the gas. If work is done on the gas (W<0) and no heat is allowed in or out, then ΔU must be positive ie. T increases. The key to cooling is the expansion. PV=nRT just tells you that T is proportional to V if P is constant. When you compress the gas, the work done in compressing increases the internal energy so T increases unless heat flows out (Q<0).

    If you run any thermodynamic engine cycle backward you can move heat the other way i.e from a cooler reservoir to a warmer reservoir by doing work. Work is done on the gas by compressing it, letting heat flow out of it and then letting it expand against an external pressure until it reaches a temperature just below the temperature of the cold reservoir (W > 0 means ΔU < 0 so T decreases).

    But the reverse engine cycle can be slow in creating a temperature difference. Modern refrigeration requires creating that cold temperature quickly. That is where the Joule-Thomson effect comes in. A gas with a high Joule-Thomson coefficient is compressed and then allowed to expand freely and adiabatically through a throttle (narrow aperture) valve. This results a significant temperature drop but no (very little) change in internal energy. That cold refrigerant is then placed in a heat exchanger to cool the space to be refrigerated. The cold fluid absorbs heat rapidly due to the significant temperature difference. The Joule-Thomson effect is at the heart of modern refrigerators and cooling systems.

    AM
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: How does a refrigerator work?
  1. How does glasses work? (Replies: 7)

  2. How does a cd work? (Replies: 1)

Loading...