sparkle123
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I know ΔA=ΔU-TΔS
how does this lead to ΔA=-integral(PdV)? (which seems like work)
how does this lead to ΔA=-integral(PdV)? (which seems like work)
The discussion revolves around the relationship between the Helmholtz free energy (ΔA) and the first law of thermodynamics, particularly in the context of thermodynamic processes. Participants are exploring how the equation ΔA=ΔU-TΔS connects to the expression ΔA=-integral(PdV).
The discussion is active, with participants providing insights into the definitions and conditions of the equations involved. There is an exploration of the assumptions necessary for the equations to hold true, particularly the constancy of temperature in certain scenarios.
Some participants note that ΔA=ΔU-TΔS is specifically applicable to isothermal processes, while the general equation dA=dU-TdS is presented as universally valid. There is also mention of the need to integrate under specific assumptions to derive the relationship between ΔA and the work done (integral(PdV)).