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How does the Wilson Line change under time reversal?

  1. Jan 22, 2015 #1
    Textbooks tell us that a four vector under time reversal changes as ##x^\mu \to \tilde x^\mu = x_\mu##, and ##i \to -i##. The gluon field changes as ##A^\mu(x) \to A_\mu(-\tilde x)##.
    My question is how does the following integral (the wilson line in the perpendicular direction) change unter time reversal?
    ##\mathcal{P} \exp\{ig\int_{\vec a_\perp}^{\vec b_\perp} dx_\perp \cdot A_\perp(x_\perp)\}##
    Can it be the following way??
    ##-ig\int_{-\vec a_\perp}^{-\vec b_\perp} dx_\perp \cdot [-A_\perp(x_\perp)]##
     
    Last edited: Jan 22, 2015
  2. jcsd
  3. Jan 27, 2015 #2
    Thanks for the post! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
     
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