How Does UV Light Initiate Chlorine Atom Splitting in Chlorination?

  • Thread starter Thread starter Cheman
  • Start date Start date
  • Tags Tags
    Mechanism
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
8 replies · 7K views
Cheman
Messages
235
Reaction score
1
Chlorination mechanism...

In chlorination, with chlroine gas and methane, why does the UV light cause the chlorine atom to split into free radicals? I know that it "supply the energy", but what actually happens?

Thanks. :wink:
 
Chemistry news on Phys.org
Yes, you form two Cl radicals. One Cl radical can then abstract a hydrogen atom from methane to make HCl and a methyl radical. The methyl radical can then combine with another Cl radical to make the product, chloromethane.
 
Well, Movies answered the question fairly well, but I think there is something with [tex]h\nu[/tex]; the energy in photon causes the sigma bond to be homolytically (just in the middle) cleaved, giving away two radicals, as Movies also wrote. The rest is very clear from his post.
 
Yes, chem_tr is right. I guess I glossed over how that actually happens. I have always thought of it as exciting the vibration of the Cl2 molecule until the Cl-Cl bond is essentially "ripped" apart.
 
Yeah I think it's to do with Eistien's E=hf and homolytic fission occurs in Cl2. The free radical is very reactive, and can therefore substitute a hydrogen from methane.
 
Thats really quite an advanced question. If you want to know the real answer, you learn it in either third semester physics (modern physics) or second semester physical chemistry.

It has to do with the energy state of the electrons in Cl-Cl bond. In this case, it happens that the electrons in the sigma bond absorb light in the frequency of the UV region, because their energy states are matched by the energy of the photon, where E = hf. The excited electrons jump up to a higher energy state, which causes the bond to "break" and disassociate homolytically.
 
Thanks so-crates - could you please elaborate further on how the bond actually breaks?
 
As he said, a single sigma bond with two electrons can be cleaved homolytically, if each electron is a sigma bonding and sigma* antibonding orbital; in this case, the bond is homolytically broken. The photonic energy is very high to supply this excitation.