How far beyond the fence does the ball strike the ground?

In summary, a baseball is hit at ground level and reaches its maximum height 3.1 seconds later. 2.6 seconds after reaching its maximum height, the ball barely clears a fence 97.2 meters away. The height of the fence is not required to solve the problem, as the ball follows a symmetrical trajectory. The first part of the problem is finding how far beyond the fence the ball strikes the ground, and the second part may involve approximating the height of the fence.
  • #1
adaxial
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Homework Statement





A baseball is hit at ground level. The ball reaches its maximum height above ground level 3.1 s after being hit. Then 2.6 s after reaching its maximum height, the ball barely clears a fence that is 97.2 m from where it was hit. Assume the ground is level.

a) How far beyond the fence does the ball strike the ground?




Homework Equations


V = x/t


The Attempt at a Solution

 
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  • #2
Welcome to the physics forums,

You should show your attempt at a solution (or at least explain your thought process, and where you're stuck at) so that you can be helped where you need it
 
  • #3
How high is the fence? That would seem to be an essential piece of information.
 
  • #4
SteamKing said:
How high is the fence? That would seem to be an essential piece of information.

You shouldn't need to know that to solve the problem
 
  • #5
I agree with Nathanael . The height of the fence is not required .
 
  • #6
Ditto. The problem is easier than it looks at first glance.
 
  • #7
this seems like more of a math question than a physics one. A hint is that the ball follows the path of a trajectory meaning that the path it takes to rise to its maximum point is symmetrical to its fall back to the ground.
 
  • #8
Nathanael said:
You shouldn't need to know that to solve the problem

Indeed. All that is needed for the OP's problem (which I note is designated as part (a)) is that the ball clears the fence. Adding "barely" suggests that part (b) of the problem is "approximately how tall is the fence?"
 
  • #9
Probably best to let the OP have a go at it now.
 

1. What is the equation for calculating the distance the ball strikes beyond the fence?

The equation for calculating the distance the ball strikes beyond the fence is d = v2sin(2θ)/g, where d is the distance, v is the initial velocity of the ball, θ is the angle of projection, and g is the acceleration due to gravity.

2. How does the angle of projection affect the distance the ball strikes beyond the fence?

The angle of projection has a direct impact on the distance the ball strikes beyond the fence. The larger the angle, the farther the ball will travel. This is because a larger angle means the ball is launched at a higher angle and will stay in the air for a longer period of time.

3. Does the initial velocity of the ball affect how far it will travel beyond the fence?

Yes, the initial velocity of the ball has a significant impact on how far it will travel beyond the fence. The higher the initial velocity, the farther the ball will travel. This is because a higher velocity means the ball has more speed and momentum, allowing it to travel a greater distance.

4. How does air resistance affect the distance the ball strikes beyond the fence?

Air resistance can have a small effect on the distance the ball strikes beyond the fence. If the ball is hit with a high initial velocity, air resistance will slow it down slightly. However, this effect is minimal and can be ignored in most calculations.

5. Is the distance the ball strikes beyond the fence affected by the height of the fence?

No, the height of the fence does not have a direct impact on the distance the ball strikes beyond it. The distance is primarily determined by the initial velocity and angle of projection of the ball. However, a higher fence may require the ball to be hit at a higher angle in order to clear it, which could potentially affect the distance it travels beyond the fence.

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