A proton travelling at v= 1.0*10^5 m/s enters the gap btwn the plates of a 2.0-cm-wide parallel-plate capacitor. The surface charge densities on the plates are +-1.0*10^6 C/m2. How far has the proton been deflected sideways when it reaches the far edge of the capacitor? I figured that the horizontal velocity would be constant so I need to find a vertical v to find how far the proton has been deflected. After that I can find the answer. So, I need to find the acceleration to find the final vertical v by using a= eE/m. The problem is I'm not sure how to find E in N/C w/ the given information. They give 1.0*10^6 C/m2 but I'm not sure how to convert that into E. Any hints/tips would be greatly appreciated.