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How fast is that proton?

  1. Feb 21, 2008 #1
    1. The problem statement, all variables and given/known data

    We are in a laboratory and there is a photon and an ultra-relativistic proton moving. The energy of the photon in the frame of reference of the laboratory is 35eV. The energy of the same photon in the frame of reference of the proton is 5MeV. What is the energy of the proton in the frame of reference of the laboratory?

    2. Relevant equations

    energy = h*f
    Relativistic doppler effect
    Lorenz velocity transformations
    relativistic energy

    3. The attempt at a solution

    using energy = h*f

    first frequency (f1) is 8.48*10^(15) Hz
    second frequency (f2) is 1.21*10^(21) Hz

    change of frequency is I guess because of Doppler effect
    because f2 > f1, the proton and the photon must be approaching each other. But no matter what, the proton will see the photon approaching with a speed of c. I am not sure if it is valid to use the Doppler formula here. If I use, I get,
    B=v/c=0,99999 (the relative speed of the photon and the proton)

    then using Lorenz velocity transformation in x direction I get the speed of the proton to be -c. I thought this could be an indication of the proton's actually to be moving away from the photon (that means both moving in the same direction)

    But then I cannot use Energy= (gama)*m*c^(2) because (gama) will be infinite.

    I'd appreciate any help.
    thanks
     
  2. jcsd
  3. Feb 21, 2008 #2
    Well I posted this response on your topic in intro physics before I noticed you moved it, here it is again in case you didn't see


    I believe you're right to use the doppler effect, but I didn't follow your application

    The relativistic doppler shift is frequency observed = sqrt[(1-v/c)/(1+v/c)]*frequency emitted from the source

    The problem is V is gonna be humongous and yes, negative

    f2/f1 is like somethingx10^35, so you get (10^35-1)=-(10^35+1)v/c

    Divide both sides by 10^35+1 and you get -v/c=a number just so very much almost 1 but just not quite, like .9999 out to 30+ decimal places

    Now when you use the equation like I did, you're assuming positive V means they're moving AWAY from each other, so the negative means the opposite of what you concluded, they're rushing towards each other, and the proton is basically going an incredibly small amount less than c. So yes gamma is gonna be gigantic to the point of ludicrous and the energy of the proton is gonna be gigantic to the point of unreasonable. But I think that's the idea

    If it were ACTUALLY going the speed of light, which you rounded off too, then yes it would have infinite energy.

    Which is the point, objects with mass don't get to go the speed of light because we can't impart infinite energy to them. So I think you did the problem right, me following or not, but reached the wrong conclusion
     
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