1. The problem statement, all variables and given/known data An arrow is fired horizontally off a cliff. The initial speed of the arrow is 280 ft/s and the arrow lands 400 feet from the base of the cliff. How high is the cliff? 2. Relevant equations t=x/v y=1/2(a)(t^2) 3. The attempt at a solution I did the horizontal component first. xinitial=400 a=0 vinital=280 ft/s x=vt t=x/v t=400/280 t=1.43 s Vertical: t=1.43 s a=9.8 m/s^2 y0=0 y=? y=1/2(a)(t^2) y=1/2(9.8)(1.43)^2 y=9.8(2.04)^2 y=20 ft tall. Is this correct? If so, why didn't I have to half my answer? Thanks in advance!