How is y=0 an odd function when it isn't symmetric to the origin?
Sure it is. Consider f(x)=0 and recall the definition of an odd function.
Note here, that for any function f in general, it's not necessary that f is either odd or even; nor that it cannot be both. You've found an example of the latter
Did you mean "odd" and "even"? f(x)= 0 is clearly a closed function, certainly not open!
It is definitely both even and odd.
Heh, just read a topology thread. I was thinking "odd" and "even", but I wrote "open" and "closed". Still a bit sleepy probably :O
I'll change my post
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