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How is Zp solved for in this problem? (Answer given)

  1. Feb 7, 2017 #1
    Rs = 0.20 Ω
    R'r = 0.17 Ω
    Xs = 0.50 Ω
    X ' r = 0.60 Ω
    Rc = 200 Ω
    Xm = 15 Ω
    at Nr = 1165, slip = (Ns- Nr)/Ns = 0.02916 ~2.92%slip
    at Nr = 1195, slip = (Ns- Nr)/Ns = 0.00416 ~0.42%slip
    Zp = j Xm || ( (R'r / s) + j X'r )
    therefore for i) slip s = 0.02916
    Zp = 5.2787 <26.36' or 4.7295 + 2.344j
    Ztotal = Zs + Zp = ( 0.2 + 0.5j) + (4.7295 + 2.344j) = 5.69<29.98'
    What do the double vertical lines mean in this case, and how is the Zp equation solved? Please show work, thank you. Also how was that equation created? (Trying to study, thanks guys)
     
  2. jcsd
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