- #1

cathliccat

- 8

- 0

As I understnd it I need to:

(heat to change ice to water)+(heat to raise water from 0degrees C to T)=(heat lost by 8g of water cooling from 100degrees C to T)

My book shows the formula for this is:

(mass of the ice*Lf) + (mass of ice*c)=(mass of water*c)(100degrees-T)

So:

m(333kJ/kg)+m(4186J/kg*degC)*(T)=.008kg(4186J/kg*degC)*(100degC-T)

The m is what I'm solving for, what do I do about the T? I know its in equilibrium, but I don't know what it is. I can't solve for both.

Thanks in advance!