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How many jk ff?

  1. Apr 29, 2004 #1
    "Design a counter using jk ff that is a 16 state device which counts (sequences) in the following sequence: 0 2 4 6 A C E 3 7 F 0"

    for 16 states, u would need 5 jk ff since 4 jk only go up to 15 right?
     
  2. jcsd
  3. Apr 29, 2004 #2
    4 JK's have 16 states--0 to 15
     
  4. Apr 29, 2004 #3
    ops. Thanks for clearing it up.
     
  5. May 3, 2004 #4
    How can I make this counter with a 74LS194 shift register and a programmed 27C256 EEPROM with the count sequences? The assigment said no shifting from the shift register.
     
  6. May 3, 2004 #5
    For the 194, how does the "do nothing" option work? There are left shift, right shift then do nothing.
     
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