1. The problem statement, all variables and given/known data[/B A bicycle with a speed 12 km/h is driving along a leveled wet road. How much ahead the front axle (see picture) does the wheel jet the water that it picks up from the floor?The radius of the wheel is r = 35 cm. Let’s suppose that the drops of water that are separating from the highest point of the wheel are flying the farthest; and we suppose that the drops are not separating from the lower part of the wheel because of the mudguard of the wheel is preventing them. What is the solution for the bicycle without the mudguard under the same condition? 2. Relevant equations ∆y= y- y0= v(0)*t- ½ gt² ∆x= x- x(0)= v(0)t 3. The attempt at a solution First I calculated time: ∆y= y- y(0)= v(0y)*t- ½ gt² y0= 0 v(0y)= 0 and I set for y= (-0.7m), because the drop is falling to the ground y= -½ gt² t= 0.38 s Now I calculated the distance: ∆x= x- x0= v(0x)*t x0= 0 v(0x)= 12 m/s t= 0.38 s x= v(0x)*t x= 1.27 m Are my attempts to solve this problem correct? Thank you!