a cart with a mass of M is moving at velocity V, a body with a mass of m falls onto the cart from a height of H and sticks to it, how much energy was lost (to heat), there is no friction.(adsbygoogle = window.adsbygoogle || []).push({});

i said that, since the mass freefalls, its velocity at the moment of impact is[tex]\sqrt{2gh}[/tex]

the momentum doesnt change so

MV+0=(m+M)Ux

0+m[tex]\sqrt{2gh}[/tex]=(m+M)Uy

is this correct? will the cart have velocity on y axis??

if there is no friction how is Ux<V

then find the total energy at the start, which is mgh+0.5MV[tex]^{2}[/tex], and subtract it from the energy at the end 0.5(m+M)[Uy[tex]^{2}[/tex]+Ux[tex]^{2}[/tex]]

is this correct

the answer in my book is

Q=mgh+V^2[tex]\frac{Mm}{2(m+M}[/tex]

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# Homework Help: How much energy was lost

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