- #1

Taiki_Kazuma

- 24

- 0

[tex]D=\frac{1}{2}*C_D*r*v^2*A[/tex]

I need to find the Force pushing against a sign that is attached to a vehicle.

The area (A) of the sign is 60"X28" which is 42.672 [tex]m^2[/tex]

The velocity (v) that the vehicle will be moving is roughly 80 miles per hour which converts to 35.7632 [tex]\frac{m}{s}[/tex]

The next 2 I'm not sure about...

Air density (r) is 1.229 [tex]\frac{Kg}{m^3}[/tex]?

and

[tex]C_D[/tex] (Coefficeitn of friction) of this sign (which the broad side will be hitting the wind head on) is 1.28?

So I did all this calculation and got

42929 N which is 9651 lbs. That is a hell of a lot of force. I was wondering if I did all this correct...please let me know. Thanks