How much heat is liberated from the complete combustion

  • Thread starter ~angel~
  • Start date
  • #1
150
0
The complete combustion of RDX is 2C3H6N6O6 + 302 --> 6H2O + 6CO2 + 6N2.

How much heat is liberated from the complete combustion of 10g of RDX?

delta H values: H20 = -286, CO2 = -394, RDX = +65 (all in kJ/mol)

I thought it'll be (6*-286 + 6*-394) - (2*65)
= -4210 kJ/mol

Then divide that by the amount of moles in 100g. But I end up with this massive number which is wrong. I'm not sure whether to take into acount the 2 moles of RDX reacting when finding the amount of moles in 100g as well.

Thanks.
 

Answers and Replies

  • #2
vsage
Why did you divide it when the units you found for [tex]\Delta H[/tex] implies you multiply by the number of moles? Also, remember the number you found is actually the heat liberated per *2* mol of RDX.
 
Last edited by a moderator:

Related Threads on How much heat is liberated from the complete combustion

Replies
1
Views
12K
Replies
3
Views
2K
  • Last Post
Replies
1
Views
8K
Replies
6
Views
6K
Replies
2
Views
9K
  • Last Post
Replies
6
Views
4K
Replies
8
Views
3K
Replies
1
Views
3K
Replies
4
Views
554
Replies
30
Views
3K
Top