How much power must you exert to horizontally drag a 20.0 kg table 14.0 m across a brick floor in 40.0 s at constant velocity, assuming the coefficient of kinetic friction between the table and floor is 0.600? 2. Relevant equations P=F(d/t), fk=mukN 3. The attempt at a solution P=(20.0*9.8)(14.0/40.0) fk=(0.600*20.0*9.8) =68.6W =117.6 117.6-68.6=49W I really do not know how to do this problem, I just tried it in a way that made some sense to me, but it's obviously wrong. PLEASE HELP!!!