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**How much will the aluminum stretch**

a 3.57 kg mass is supported by an aluminum wire with a length of 2.43 m and a diameter of 2.01mm. How much will the wire stretch?

Young's Modolus for Al= 6.9 * 10^10

First get the cross sectional area of the Al

then plug it into the formula

Y = Fl/A(delta)l

I come out with like 2572 m which just doesn't

*seem*right. Where am I going wrong? I have checked the math and averything is in m and kg.

HELP

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