1. The problem statement, all variables and given/known data Question A 7.6 kg body is at rest on a frictionless horizontal air track when a constant horizontal force F with arrow acting in the positive direction of an x axis along the track is applied to the body. A stroboscopic graph of the position of the body as it slides to the right is shown in the figure. The force F with arrow is applied to the body at t = 0, and the graph records the position of the body at 0.50 s intervals. How much work is done on the body by the applied force F with arrow between t = 0 and t = 0.5 s? 2. Relevant equations x=vot +1/2at^2 v=at m/2(Vf^2-Vi^2) 3. The attempt at a solution When I work the problem I get 0.152 Joules. .8 = 1/2 a(2.0)^2 a=0.4 v=0.4(0.5) v=0.2 1/2(7.6kg)(.2^2)= 0.152J. I work it this way and I have no idea why it is wrong. The answer is supposed to be 0.0973.