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How much work will be done?

  1. Aug 6, 2013 #1
    1. Given the set-up in Figure 1, how much work will be done after part of the weight is removed, as shown in Figure 2, knowing only the height the piston rises?



    2. W=mC[P](T[2]-T[1])+mg(h[2]-h[1])



    3. W=mC[P](T[2]-T[1])+(m[2]-m[1])g(h[2]-h[1])

    figure.png
     
    Last edited: Aug 7, 2013
  2. jcsd
  3. Aug 7, 2013 #2

    Simon Bridge

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    I think you need to go through your posts and explain how you have approached each problem so that we can give you answers that will make sense to you.
     
  4. Aug 7, 2013 #3

    rude man

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    Is this isothermal, adiabatic or what?
     
  5. Aug 8, 2013 #4

    Simon Bridge

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    Indeed - the equations won't make much sense without some discussion.
    The use of ##C_p## kinda suggests constant pressure is assumed doesn't it?
     
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