# Homework Help: How should I interpret?

1. Oct 27, 2006

### quasar987

I got this HW question made up by the professor that I find ambiguous. It says

Consider the curve $\theta (t)=\pi/2-t$, $\phi(t)=\log \cot(\pi/4-t/2)$ on the sphere $r(\theta,\phi)=(\sin\theta \cos\phi,\sin\theta\sin\phi,cos\theta)$

Find the lenght of the curve btw the points t=pi/6 and pi/4

He did not specify domains for either the curve nor the "surface" r. On one hand, if we take r to be a surface patch, this requires that the (maximum) domain be $0 < \theta < \pi$, $0 < \phi < 2\pi$. Anything bigger and the domain is not open or r is not injective. But this surface patch does not cover the whole sphere.

I could also consider two other surface patches of the form $r_{2,3}(\theta,\phi)=(\sin\theta \cos\phi,\sin\theta\sin\phi,cos\theta)$ with appropriate domains, that together with r above form an atlas for the unit sphere.

Any thoughts? How would you interpret this question?

Last edited: Oct 27, 2006
2. Oct 27, 2006

### StatusX

I don't know what you mean. The domain is pi/6<t<pi/4. From the above relations you can get r as a function of t, and this is just some curve.

3. Oct 27, 2006

### quasar987

There is another question after that:

Find the angles of intersection btw this curve and the parallels $\theta = const.$

would you still say that the curve's domain is (pi/6,pi/4)? Or would you study it more carefully to find what is the maximum domain where the curve is defined and thus find all the possible intersectino points?

4. Oct 27, 2006

### StatusX

I would stick to (pi/6,pi/4), at least for this question. If you're curious, keep going, but then you're doing more than what's asked.