# How to apply comparison test?

## Homework Statement

Is the series convergent or divergent? $$\sum_{n=0}^{\infty}{\frac{1}{\sqrt{n+1}}}$$

## Homework Equations

I can use any test but wolfram alpha says that it is divergent by comparison test.

## The Attempt at a Solution

How do I apply comparison test?

I can compare it to: $$\sum _{ n=0 }^{ \infty }{ \frac { 1 }{ \sqrt { n } } }$$ but the second series is greater than the series in the question and the second series is divegent. :(

LCKurtz
Homework Helper
Gold Member

## Homework Statement

Is the series convergent or divergent? $$\sum_{n=0}^{\infty}{\frac{1}{\sqrt{n+1}}}$$

## Homework Equations

I can use any test but wolfram alpha says that it is divergent by comparison test.

## The Attempt at a Solution

How do I apply comparison test?

I can compare it to: $$\sum _{ n=0 }^{ \infty }{ \frac { 1 }{ \sqrt { n } } }$$ but the second series is greater than the series in the question and the second series is divegent. :(

Have you had the "generalized comparison test"? That's what you want.

Have you had the "generalized comparison test"? That's what you want.

You mean the limit comparison test? Yes, I've learned both the comparison test and the limit comparison test.

Currently trying to use the second series for limit comparison test.

LCKurtz
Homework Helper
Gold Member
Yes. That should work.

Wait. I found an easier method. Just let k=n+1.

LCKurtz
Homework Helper
Gold Member
Yes, that's pretty slick. Still, the limit comparison test is your friend and you want to be adept at recognizing when and how to use it. Your idea won't work on lots of similar problems that are just a little bit more complicated.

I just realized that my second limit does not make sense since when n=0, you get 1/0.

What do I use for limit comparison test? :(

LCKurtz